△ABC中,若AC=2,BC=7,AB=3,则cosA=_.

问题描述:

△ABC中,若AC=

2
,BC=
7
,AB=3,则cosA=______.

△ABC中,∵AC=

2
,BC=
7
,AB=3,
(
2
)
2
+(
7
)
2
=32,即AC2+BC2=AB2
∴△ABC是直角三角形,且∠C=90°.
∴cosA=
AC
AB
=
2
3