(log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题.

log(2)9=2log(2)3=2*(lg3/lg2)log(4)1/9=-2log(4)3=-2(lg3/lg4)=-2（lg3/2lg2）log(9)0.5=-log(9)2=-lg2/2lg3log(3)2=lg2/lg3把化简的代入计算1/lg2-1/lg3或log(2)10-log(3)10这是我化得最简结果了,就是不知道对不对...(log(2)9+log(4)1/9)*(log(3)2+log(9)0.5)=(log(2)3^2+log(4)3^-2)(log(3)2+log(9)2^-1)=(2log(2)3-2log(4)3)(log(3)2-log(9)2)=2log(2)3*log(3)2-2log(2)3*log(9)2-2log(4)3*log(3)2+2log(4)3*log(9)2=2*lg3/lg2*lg2/lg3-2*lg3/lg2*lg2/2lg3-2*lg3/2lg2*lg2/lg3+2*lg3/2lg2*lg2/2lg3=2-1-1+1/2=1/2 谢谢你动手算，不过答案我算出来了！