(2+1)(2^2+1)(2^4+1)*(2^512+1)的末位数字是?
问题描述：
(2+1)(2^2+1)(2^4+1)*(2^512+1)的末位数字是?
答
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)(2^256+1)(2^512+1)/(2-1)=(2^2-1)(2^2+1).(2^512+1)=...=(2^512-1)(2^512+1)=(2^1024-1) 七啊