圆x^2+y^2-2ax+a^2=2和圆x^2+y^2-2by+b^2=1外离,则a,b满足的条件是?
问题描述:
圆x^2+y^2-2ax+a^2=2和圆x^2+y^2-2by+b^2=1外离,则a,b满足的条件是?
RT
答
(x-a)^2+y^2=2
x^2+(y-b)^2=1
根号(a^2+b^2)>根号2+1