(2sin2α/1+cos2α)*(cosα)^2/cos2α=?
问题描述:
(2sin2α/1+cos2α)*(cosα)^2/cos2α=?
答
(2sin2α/1+cos2α)*(cosα)^2/cos2α
=2tana*(cosα)^2/cos2α
=2tana*(cosα)^2/cos2α
=2sinα*cosα/cos2α
=sin2α/cos2α
=tan2a