已知等比数列{an}的首项a1=1,公比q=2,则log2a1+log2a2+…+log2a11=( ) A.46 B.35 C.55 D.50
问题描述:
已知等比数列{an}的首项a1=1,公比q=2,则log2a1+log2a2+…+log2a11=( )
A. 46
B. 35
C. 55
D. 50
答
∵等比数列{an}的首项a1=1,公比q=2,
∴log2a1+log2a2+…+log2a11
=log2(a1a2…a11)
=log2(a110q1+2+3+…+10)
=log2255
=55.
故答案为:55.