a^2-1分之2a+1*a^2-a分之a^2-2a+1-a+1分之1,其中a等于2分之1
问题描述:
a^2-1分之2a+1*a^2-a分之a^2-2a+1-a+1分之1,其中a等于2分之1
答
原式=(2a+1)/(a+1)(a-1)*(a-1)²/a(a-1)-1/(a+1)
=(2a+1)/(a+1)(a-1)*(a-1)/a-1/(a+1)
=(2a+1)/a(a+1)-a/a(a+1)
=(2a+1-a)/a(a+1)
=(a+1)/a(a+1)
=1/a
=1/(1/2)
=2