先化简,后求值 2(a+根号3)(a-根号3)-a(a-6)+6 a=根号2-1

问题描述:

先化简,后求值 2(a+根号3)(a-根号3)-a(a-6)+6 a=根号2-1

2(a+根号3)(a-根号3)-a(a-6)+6 =2(a-3)-a+6a+6 =2a-6-a+6a+6 =a+6a 当a=根号2-1时,原式=(根号2-1)+6(根号2-1) =2-2根号2+1+6根号2-6 =-3+4根号2