已知x2+3x=6,求x3+x2-12x+10的值
问题描述：
已知x2+3x=6,求x3+x2-12x+10的值
要对的 .
x2+3x=6==>x^2+3x-6=0 x^3+x^2-12x+10 =x^3+3x^2-2x^2-6x-6x+10 =x^3+3x^2-6x-2x^2-6x+10 =x(x^2+3..这个答案不要.
答
x2+3x=6
x^2=6-3x
x3+x2-12x+10
=x(6-3x)+x^2-12x+10
=-2x^2-6x+10
=-2(x^2+3x)+10
=-2*6+10
=-2