因式分解 x²+(2根号2)x+2根号2-2
问题描述:
因式分解 x²+(2根号2)x+2根号2-2
答
x²+(2√2)x+2√2-2=(x+√2)²+2√2-4=-[x-√2-√(4-2√2)][x-√2+√(4-2√2)]
因式分解 x²+(2根号2)x+2根号2-2
x²+(2√2)x+2√2-2=(x+√2)²+2√2-4=-[x-√2-√(4-2√2)][x-√2+√(4-2√2)]