(1)解不等式组5x-1>2x+5x-4<3x+1 (2)化简:x+1/x÷ x2-1x2.

问题描述:

(1)解不等式组

5x-1>2x+5
x-4<3x+1
           
(2)化简:
x+1
x
÷ 
x2-1
x2

(1)

5x-1>2x+5①
x-4<3x+1②

解不等式①得x>2,
解不等式②得x>-2.5,
所以不等式组的解集为x>2;
(2)原式=
x+1
x
x
(x+1)(x-1)

=
1
x-1