求y=10^(xtan2x)的导数
问题描述:
求y=10^(xtan2x)的导数
答
y′=【10^(xtan2x)】′
=ln10*10^(xtan2x)[(xtan2x)]′
=ln10*10^(xtan2x)[1*tan2x+x*(tan2x)′]
=ln10*10^(xtan2x)[1*tan2x+x*2/(cos2x)^2]对不起答案有错你在认真看看吧,思路没问题的。就是xtan2x的导数哪里那应该是(tan2x)′的求法问题(tan2x)′=(sin2x/cos2x)′=【(sin2x)′cos2x-sin2x*(cos2x)′】/(cos2x)^2=【2(cos2x)*cos2x-sin2x*(-sin2x)*2】/(cos2x)^2=2((cos2x)²+(sin2x)²】/(cos2x)²=2/(cos2x)²依旧没错