若x→0时,(1−ax2)1/4−1 与xsinx是等价无穷小,则a=_.
问题描述:
若x→0时,(1−ax2)
−1 与xsinx是等价无穷小,则a=______. 1 4
答
当x→0时,(1−ax2)
−1~−1 4
ax2, xsinx~x21 4
于是,根据题设有
lim x→0
=(1−ax2)
1 4 xsinx
lim x→0
=−−
ax2
1 4 x2
a=11 4
故:a=-4