计算:8/(4x^2-1)+(2x+3)/(1-2x)=-1
问题描述：
计算:8/(4x^2-1)+(2x+3)/(1-2x)=-1
化简:2x/(x^2+2x+1)+1-x/(x+1)-(x^2-x)/(x^2-1)
答
8/(4x^2-1)+(2x+3)/(1-2x)=-1 8/(4x^2-1)-(2x+3)/(2x-1)=-1 8/(4x^2-1)-(2x+3)(2x+1)/(2x-1)(2x+1)=-1[8-(2x+3)(2x+1)]/(4x^2-1)=-18-(4x^2+8x+3)=-(4x^2-1)-8x+5=1x=1/2代入检验,x=1/2使得分母1-2x和4x^2-1=0.舍去...