解一元二次方程:x-(5√2)x+2=0
问题描述:
解一元二次方程:x-(5√2)x+2=0
答
x-(5√2)x+2=0b^2-4ac =50-8 =42 X1=(-b+根号(b^2-4ac)/2a =( 5√2+ √42)/2 X2=(-b-根号(b^2-4ac)/2a =( 5√2- √42)/2
解一元二次方程:x-(5√2)x+2=0
x-(5√2)x+2=0b^2-4ac =50-8 =42 X1=(-b+根号(b^2-4ac)/2a =( 5√2+ √42)/2 X2=(-b-根号(b^2-4ac)/2a =( 5√2- √42)/2