现要配制500mL 1mol/L硫酸溶液,需用质量分数为98%,密度为1.84g/cm3的浓硫酸_mL.

问题描述:

现要配制500mL 1mol/L硫酸溶液,需用质量分数为98%,密度为1.84g/cm3的浓硫酸______mL.

n(H2SO4)=c•V=1mol/L×0.5L=0.5mol,m(H2SO4)=0.5mol×98g/mol=49g,
浓硫酸溶液的质量=

49g
98%
=50g,浓硫酸溶液的体积V=
m
ρ
=
50g
1.84g/cm3
=27.17ml,
故答案为:27.17.