(x²-7x+6)×(x²-x-6)+56 因式分解
问题描述:
(x²-7x+6)×(x²-x-6)+56 因式分解
答
(x^2-7x+6)(x^2-x-6)+56 =(x-6)(x-1)(x-3)(x+2)+56=[(x-6)(x+2)][(x-1)(x-3)]+56=(x^2-4x-12)(x^2-4x+3)+56=(x^2-4x)^2-9(x^2-4x)-36+56=(x^2-4x)^2-9(x^2-4x)+20=(x^2-4x-4)(x^2-4x-5)=(x^2-4x-4)(x-5)(x+1)=(x-2+2...