xy'-y-y*y=0的通解
问题描述：
xy'-y-y*y=0的通解
答
∵xy'-y-y²=0 ==>xdy/dx=y(y+1)==>dy/[y(y+1)]=dx/x==>[1/y-1/(y+1)]dy=dx/x==>ln│y│-ln│y+1│=ln│x│+ln│C│ (C≠0是积分常数)==>y/(y+1)=Cx∴原微分方程的通解是y/(y+1)=Cx (C≠0是积分常数)....