已知xy=根号3,x-y=3根号3-2,求(x+1))(y-1)的值

问题描述:

已知xy=根号3,x-y=3根号3-2,求(x+1))(y-1)的值

(x+1)(y-1)
=xy-x+y-1
=xy-(x-y)-1
=√3-(3√3-2)-1
=√3-3√3+2-1
=1-2√3