用加减消元法解二元一次方程组:①[(x+y)/2]+[(x-y)/3]=5②[(x+y)/2]+[(x-y)/3]=-1 具体一点!
问题描述:
用加减消元法解二元一次方程组:①[(x+y)/2]+[(x-y)/3]=5②[(x+y)/2]+[(x-y)/3]=-1 具体一点!
答
①[(x+y)/2]+[(x-y)/3]=5
②[(x+y)/2]+[(x-y)/3]=-1
①-②
(x-y)/3=6
x-y=18,x+y=2
相加
2x=20,x=10,则y=-8