先化简再求值:(x2-x)/(x-1)*(x2-1)/(x2-2x+1)其中满足方程x2-3x+2=0

问题描述:

先化简再求值:(x2-x)/(x-1)*(x2-1)/(x2-2x+1)其中满足方程x2-3x+2=0

x²-3x+2=0
(x-1)(x-2)=0
因为分母x-1≠0
所以x-2=0
x=2
原式=x(x-1)/(x-1)*(x+1)(x-1)/(x-1)²
=x*(x+1)/(x-1)
=2*3/1
=6