2道分式加减法.(2/3a²)+(3/4b)-(5/6ab)=?(a+2b/a-b)+(b/b-a)-(2a/a-b)=?
问题描述:
2道分式加减法.(2/3a²)+(3/4b)-(5/6ab)=?(a+2b/a-b)+(b/b-a)-(2a/a-b)=?
答
2/(3a^2)+3/(4b)-5/(6ab)=2*4b/(12a^2b)+3*3a^2/(12a^2b)-5*2a/(12a^2b)=(9a^2-10a+8b)/(12a^2b)(a+2b)/(a-b)+ b/(b-a)- 2a/(a-b)=(a+2b)/(a-b)- b/(a-b)- 2a/(a-b)={(a+2b)- b- 2a}/(a-b)=-(a+b)/(a-b)...