一、i(2-i)(1-2i) 二、5(4+i)^2/i(2+i)
问题描述:
一、i(2-i)(1-2i) 二、5(4+i)^2/i(2+i)
答
1.=(1+2i)(1-2i)=1-(2i)^2=5
2.=5(4+i)^2/(-1+2i)=(-1-2i)*(4+i)^2=(-1-2i)(15+8i)=1-38i
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