如图,在△ABC中,AB=BD=AC,AD=CD,则∠ADB的度数是( ) A.36° B.45° C.60° D.72°
问题描述:
如图,在△ABC中,AB=BD=AC,AD=CD,则∠ADB的度数是( )
A. 36°
B. 45°
C. 60°
D. 72°
答
∵AB=BD=AC
∴∠BAD=∠BDA,∠B=∠C
∵AD=CD
∴∠DAC=∠C=∠B
∵∠B+∠C+∠BAD+∠DAC=180°
∴∠ADB+3∠C=180°
∵∠ADB=∠DAC+∠C
∴∠ADB=2∠C
∴5∠C=180°,即∠C=36°
∴∠ADB=2∠C=72°
故选D.