函数f(X)=根号sin(-2x+π/3)的单调递增区间为
问题描述:
函数f(X)=根号sin(-2x+π/3)的单调递增区间为
答
f(x)=√sin(-2x+π/3)=√[-sin(2x-π/3)],其定义域为kπ+2π/3呵这个答案kπ+2π/3