12 34 5 (6 7 8 9) 2=2008用+ - *怎么算?

问题描述:

12 34 5 (6 7 8 9) 2=2008用+ - *怎么算?
你用什么算的啊?这么多?编程序了吧?

、=2008,113个: 1+(23-4*5)*(678-9)=2008,12*(34*5+6-78/9)=2008 1234+(5*6+7*8)*9=2008,1+(2*(3-4)+5)*(678-9)=2008 (1+2)*(3/(4+5)+678-9)=2008,1+(2/(3-4)+5)*(678-9)=2008 1-(2+(3-4)*5)*(678-9)=2008,1-(2*3-4...