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分式计算：x^2-4/x^2+6x+9÷x+2/x+3 a/(a-2)-4a/a^2-4 1/(x-y)-1/(x+y)*x^2-2xy+y^2/(y+1)^2-(y-1)^2

分类: 作业答案 • 2021-12-28 15:59:06
问题描述：

分式计算：x^2-4/x^2+6x+9÷x+2/x+3 a/(a-2)-4a/a^2-4 1/(x-y)-1/(x+y)*x^2-2xy+y^2/(y+1)^2-(y-1)^2
x^2-4/x^2+6x+9÷x+2/x+3
a/(a-2)-4a/a^2-4
1/(x-y)-1/(x+y)*x^2-2xy+y^2/(y+1)^2-(y-1)^2

答

x^2-4/x^2+6x+9÷x+2/x+3=(x²-4)/(x²+6x+9)÷(x+2)/(x+3)=(x+2)(x-2)/(x+3)²×(x+3)/(x+2)=(x-2)/(x+3)a/(a-2)-4a/a^2-4=a/(a-2)-4a/(a+2)(a-2)=a(a+2)/(a+2)(a-2)-4a/(a+2)(a-2)=(a²+2a-4a)/(a...

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