(m^2+2m)^2-(2m+4n^2)^2因式分解快
问题描述：
(m^2+2m)^2-(2m+4n^2)^2因式分解
快
答
(m^2+2m)^2-(2m+4n^2)^2因式分解
解，得：
==[(m^2+2m)+(2m+4n^2)]*[(m^2+2m)-(2m+4n^2)]
==(m^2+2m+2m+4n^2)*(m^2+2m-2m-4n^2)
==(m^2+4m+4n^2)*(m^2-4n^2)
==(m^2+4m+4n^2)*(m-2n)(m+2n)
答
(m^2+2m)^2-(2m+4n^2)^2
=(m^2+2m+2m+4n^2)(m^2+2m-2m-4n^2)
=(m^2+4m+4n^2)(m+2n)(m-2n)
答
(m^2+2m)^2-(2m+4n^2)^2
=[（m²+2m)+(2m+4n²)][（m²+2m)-(2m+4n²)]
=(m²+4m+4n²)(m²-4n²)
=(m+2n)(m-2n)(m²+4m+4n²)