计算:(6x^2-4x-3)+(x^2+4x+1)
问题描述:
计算:(6x^2-4x-3)+(x^2+4x+1)
答
(6x²-4x-3)+(x²+4x+1)
= 7x²-2
计算:(6x^2-4x-3)+(x^2+4x+1)
(6x²-4x-3)+(x²+4x+1)
= 7x²-2