已知函数f(x)=Asin(2x+φ) (A>0,0
问题描述：
已知函数f(x)=Asin(2x+φ) (A>0,0
答
(1) 最大值为1,则A=1,
又 √3/2=sin(π/3 +φ),0(2)f(x)=sin(2x+π/3)
令2kπ-π/2≤2x+π/3≤2kπ+π/2
解得 kπ-5π/12≤x≤kπ+π/12
所以 增区间为[ kπ-5π/12,kπ+π/12],k∈Z