(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1计算方法是什么?
问题描述:
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1计算方法是什么?
答
因为(2-1)=1所以可以给原式乘上(2-1),原式的值不变原式=(2-1)(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1...