X/2=Y/3=Z/4 2X-Y+3Z=26 2元1次方程
问题描述:
X/2=Y/3=Z/4 2X-Y+3Z=26 2元1次方程
答
X/2=Y/3=Z/4=K
X=2K,Y=3K,Z=4K
∵2X-Y+3Z=26
把上面三个式子带入,得:
4K-3K+12K=26
13K=26
K=2
∴X=4,Y=6,Z=8