请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)=?csc(x+π/2)=?还有sin(x+π)=?cos(x+π)=?tan(x+π)=?cot(x+π)=?sec(x+π)=?csc(x+π)=?
问题描述：
请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)=?csc(x+π/2)=?
还有sin(x+π)=?cos(x+π)=?tan(x+π)=?cot(x+π)=?sec(x+π)=?csc(x+π)=?
答
sin(x+π)=-sinx,cos(x+π)=-cosx,tan(x+π)=sin(x+π)÷cos(x+π)=（-sinx）÷（-cosx）=tan x,cot(x+π)= cot x,sec(x+π)=1÷cos(x+π)=1÷(-cosx)=(-1/cos x),csc(x+π)=1÷sin(x+π)=1÷(-sinx)=(-1/sin x)
不懂详细看一下高中数学课本，会有的！
答
sin(x+π/2)=cosx cos(x+π/2)=-sinx
答
sin(x+π/2)=cos xcos(x+π/2)=-sinxtan(x+π/2)=sin(x+π/2)÷cos(x+π/2)=cos x÷(-sinx) = -cotxcot(x+π/2)=1÷tan(x+π/2)=1÷（-cotx）= - tan xsec(x+π/2)=1÷cos(x+π/2)=1÷(-sinx)=(-1/sinx)csc(x+π/2)=...