4x²-[2x-(x²-2x+3)-2(x²-3x)] 计算

问题描述:

4x²-[2x-(x²-2x+3)-2(x²-3x)] 计算

4x²-[2x-(x²-2x+3)-2(x²-3x)]
=4x²-2x+(x²-2x+3)+2(x²-3x)]
=4x²-2x+x²-2x+3+2x²-6x
=7x²-10x+3