Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简

问题描述:

Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简

=sinx/2+根号3cosx/2+sinx-根号3cosx-根号3(-cosx/2+根号3sinx/2)
=3sinx/2-根号3cosx/2+根号3cosx/2-3sinx/2
=0