若x<y<0,则x2−2xy+y2+x2+2xy+y2=( ) A.2x B.2y C.-2x D.-2y
问题描述:
若x<y<0,则
+
x2−2xy+y2
=( )
x2+2xy+y2
A. 2x
B. 2y
C. -2x
D. -2y
答
∵x<y<0,
∴x-y<0,x+y<0.
∴
=
x2−2xy+y2
=|x-y|=y-x.
(x−y)2
=
x2+2xy+y2
=|x+y|=-x-y.
(x+y)2
∴
+
x2−2xy+y2
=-2x,
x2+2xy+y2
故选C.