用公式法解方程：x^2-(√6+√2)x+2√3=0 x^2-(2-2√2)x+3-2√2=0
问题描述：
用公式法解方程：x^2-(√6+√2)x+2√3=0 x^2-(2-2√2)x+3-2√2=0
答
x^2-(√6+√2)x+2√3=0
(x-√6)(x-√2)=0
x1=√6,x2=√2
x^2-(2-2√2)x+3-2√2=0
(x-1)(x-2-2√2)=0
x1=1,x2=2-2√2