解分式方程:(1)3/(x-1)=2/(x-2);(2)(2x²+1)/(x+2)=2x;(3)x/(x+1)+(x-1)/x=2;
问题描述:
解分式方程:(1)3/(x-1)=2/(x-2);(2)(2x²+1)/(x+2)=2x;(3)x/(x+1)+(x-1)/x=2;
(4)2/(x+1)+3/(x-1)=6/(x²-1)
答
(1)3/(x-1)=2/(x-2)3(x-2)=2(x-1)x=4(2)(2x²+1)/(x+2)=2x2x²+1=2x(x+2)x=1/4(3)x/(x+1)+(x-1)/x=2(x²+x²-1)/x(x+1)=22x²-1=2x(x+1)x=-1/2(4)2/(x+1)+3/(x-1)=6/(x²-1)(2x-2+3x+3)/(x&...