x²-4x+1=0 3(x-2)²=(x-2)

问题描述:

x²-4x+1=0 3(x-2)²=(x-2)

x平方-4x+1=0
x平方-4x+4=3
(x-2)平方=3
x-2=±√3
x=2±√3
3(x-2)平方=(x-2)
3(x-2)平方-(x-2)=0
[3(x-2)-1](x-2)=0
(3x-7)(x-2)=0
x1=7/3 x2=2