x+y=-3,xy=-2,求x³y²+x²y³的值

问题描述:

x+y=-3,xy=-2,求x³y²+x²y³的值

答:
x+y=-3,xy=-2
x³y²+x²y³
=x²y²(x+y)
=(-2)*(-2)*(-3)
=-12