因式分解:a(x-y)的n次方-b(y-x)的n+1次方
问题描述:
因式分解:a(x-y)的n次方-b(y-x)的n+1次方
答
a(x-y)^n-b(y-x)^(n+1)
=a(x-y)^n-b(x-y)^(n+1)*(-1)^(n+1)
=(x-y)^n*[a-b*(-1)^(n+1)*(x-y)]