化简求值：x-y/x²-2xy+y²-xy+y²/x²-y²,其中(x-2)²+y-3的绝对值=0【很急,
问题描述：
化简求值：x-y/x²-2xy+y²-xy+y²/x²-y²,其中(x-2)²+y-3的绝对值=0【很急,
答
(x-2)²+∣y-3∣=0
(x-2)²=0,∣y-3∣=0
x=2
y=3
(x-y)/(x²-2xy+y²)-(xy+y²)/(x²-y²)
=(x-y)/(x-y)²-y(x+y)/(x-y)(x+y)
=1/(x-y)-y/(x-y)
=(1-y)/(x-y)
=(1-3)/(2-3)
=-2/(-1)
=2