把根号外的因式移到根号内; (1-x)根号x-1分之1
问题描述:
把根号外的因式移到根号内; (1-x)根号x-1分之1
答
1/(x-1)>=0
1-x所以原式=-(x-1)√[1/(x-1)]
=-√[(x-1)²*1/(x-1)]
=-√(x-1)