因式分解:(2x一1)(3x一1)(2x一3)(3x+2)十10,

问题描述:

因式分解:(2x一1)(3x一1)(2x一3)(3x+2)十10,

原式=(6x2-5x+1)(6x2-5x-6)+10
=(6x2-5x+1)(6x2-5x+1-7)+10
=(6x2-5x+1)2—7(6x2-5x+1)+10
=(6x2-5x+1-2)(6x2-5x+1-5)
=(6X2-5X-1)(6X2-5X-4)