A=(3/2)*(5/4)*(7/6)*(9/8).(2005/2004) 证明"31
问题描述：
A=(3/2)*(5/4)*(7/6)*(9/8).(2005/2004) 证明"31
答
3/2>4/3
5/4>6/5
.
2005/2004>2006/2005
(3/2)*(5/4)*.(2005/2004)>(4/3)*(6/5)*.(2006/2005)
[(3/2)*(5/4)*.(2005/2004)]^2>(3/2)*(5/4)*.(2005/2004)*(4/3)*(6/5)*.(2006/2005)=3/2*4/3*5/4*6/5*...*2005/2004*2006/2005=2006/2=1003
即A^2>1003,所以A>根号下1003>31
同理A^2