解不等式:(2x-3)(x-4)-(x+2)(x-3)≥x^2-8
问题描述:
解不等式:(2x-3)(x-4)-(x+2)(x-3)≥x^2-8
答
化简就行
(2x-3)(x-4)-(x+2)(x-3)≥x^2-8
(2x^2-11x+12)-(x^2-x-6)-x^2+8>=0
-10x+26>=0
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