函数f(x)=(x-6)/(x^2-4x-12)的连续区间为_____,间断点是______?
问题描述：
函数f(x)=(x-6)/(x^2-4x-12)的连续区间为_____,间断点是______?
答
f(x)=(x-6)/(x^2-4x-12)=(x-6)/(x-6)(x+2)
函数f(x)=(x-6)/(x^2-4x-12)的连续区间为(-无穷,-2)∪(-2,+无穷)间断点是x=-2