解不等式 x-1/x+1≥2
问题描述:
解不等式 x-1/x+1≥2
答
解由x-1/x+1≥2得x-1/x+1-2≥0即x-1/x+1-2(x+1)/(x+1)≥0即[x-1-2(x+1)]/(x+1)≥0即(-x-3)/(x+1)≥0即(x+3)/(x+1)≤0即(x+3)(x+1)≤0且x+1≠0即解得-3≤x<-1故不等式 x-1/x+1≥2的解集为{x/-3≤x<-1}...