已知sin(π-α)=-2sin(π2+α),则sinα•cosα= _ .

问题描述:

已知sin(π-α)=-2sin(

π
2
+α),则sinα•cosα= ___ .

∵sin(π-α)=sinα,sin(π2+α)=cosα,∴sin(π-α)=-2sin(π2+α)变形为:sinα=-2cosα①,∴sinα与cosα符号不同,又sin2α+cos2α=1②,把①代入②得:cos2α=15,解得|cosα|=55,所以|sinα|=255...