求函数y＝（x－1）三次根号下x^2的极值
问题描述：
求函数y＝（x－1）三次根号下x^2的极值
答
y'=[(x-1)x^2/3]'
=x^2/3+(x-1)x^-1/3
=x^2/3+x^2/3-x^-1/3
=2x^2/3-x^-1/3
=2x-1/x^-1/3
J=1/2